SBI PO Data Interpretation Practice Set - 10

1 . Directions (Q. 1 – 5) : The following pie-charts show the percentage distribution of the total employees of two Companies A and B in different departments, and the table shows the ratio of Male to Female employees in all the departments of Company A and B. The total number of employees working in Company A and B are 8000 and 7500 respectively. $Q.$ What is the total number of Female employees in $D_ 5$ of Company A and B together? A.   705 B.   710 C.   715 D.   725 2 . The total number of Female employees in $D_ 1$ of Company B is approximately how much per cent more than the number of Female employees in $D_ 1$ of Company A? A.   5% B.   7.5% C.   15% D.   22.5% 3 . What is the difference between the total Male employees of Company A and the total Female employees of Company B? A.   1230 B.   1232 C.   1234 D.   1236 4 . The average number of Male employees in $D_ 1$ and $D_ 2$ of Company B is approximately what percentage of the average number of Female employees in $D_ 5$ and $D_ 6$ of Company A? A.   177.5% B.   197.5% C.   212.5% D.   217.5% 5 . The total number of Females working in Company A is approximately what percentage of total employees of Company A? A.   42.12% B.   43.48% C.   44.24% D.   45.64% 6 . Directions (Q. 6 - 10) : Following pie-chart shows the proportion of number of students of different schools. The table shows the percentage of girls among them. $Q.$ If the number of girls in School D is 462, what is the total number of the students in School C? A.   820 B.   840 C.   860 D.   880 7 . If the total number of students in School A is 1760, what is the total number of boys in School B? A.   1303 B.   1306 C.   1309 D.   1310 8 . If the total number of students in all six schools together is 11000, what is the difference between the number of boys and that of girls in School E? A.   260 B.   264 C.   268 D.   272 9 . If the total number of boys in School D is 858, what is the average number of girls in School C and D together? A.   425 B.   426 C.   427 D.   429 10 . If the total number of boys in School F is 1936 then the number of girls in School F is what percentage of the total number of students in all the six schools together? A.   12.8% B.   13.2% C.   13.6% D.   14.4%

Answers & Solutions   1 .     Answer : Option D Explanation : Number of Female employees of Company A in department $D_5$ = 8000 x $10\over 100$ x $2\over 5$ Number of Female employees of Company B in department $D_5$ = 7500 x $10\over 100$ x $27\over 50$ Total = 320 + 405 = 725 2 .     Answer : Option A Explanation : Number of Fe mal e empl oyee s in department D, of Company B = 7500 x $24 \over 100$ x $7\over 20$ = 630 Number of Female employees in department D$_1$ of Company A = 8000 x $20\over 100$ x $3\over 8$ = 600 Reqd % = $(630 - 600)\over 600$ x 100 = $3000 \over 600$ = 5 % 3 .     Answer : Option B Explanation : Total Male employees of Company A = 1000 + 765 + 600 + 896 + 480 + 720 = 4461 Total Female employees of Company B = 630 + 504 + 720 + 520 + 405 + 450 = 3229 Difference = 4461 – 3229 = 1232 4 .     Answer : Option D Explanation : Average number of Female employees number of Company B = $D_1 + D_2\over 2$ = $1170 + 396 \over 2$ = $1566\over 2$ = 783 Average of Company A = $D_5 + D_6\over 2$ = $320 + 400 \over 2$ = $720 \over 2$ = 360 Reqd % = $783 \over 360$ x 100 = 217.5 % 5 .     Answer : Option C Explanation : Total number of Female employees of Company A = 600 + 595 + 840 + 784 + 320 + 400 = 3539 Total employees of company A = 8000 Reqd % = $3539\over8000$ x 100 = 44.2375 $\cong$ 44.24 % 6 .     Answer : Option D Explanation : Girls in D are 35%. So total number of students in D = $462 x 100\over 35$ = 1320 Total number of students in C = $28.8 \over 360$ {$360 \times 1320\over 43.2$} = 880 7 .     Answer : Option C Explanation : Boys$_B$ = {$1760 \times 360\over 57.6$} x $61.2\over 360$ x $70\over 100$ = 1309 8 .     Answer : Option B Explanation : The total number of students in E = 11000 x $54\over360$ = 1650 No.of girls in E = 1650 x $42 \over 100$ = 693 No.of boys in E = 1650 - 693 = 957 Number of boys in E = 1650 - 693 = 957 Difference = 957 - 693 = 264 9 .     Answer : Option D Explanation : Number of girls in D = $858 \times 35\over 65$ = 462 Number of girls in C = {$28.8\over 43.2$ x (462 + 858)} x $45\over100$ = 396 Average = $396 + 462\over 2$ = 429 10 .     Answer : Option D Explanation : Number of girls in F = $45 \times 1936 \over 55$ = 1584 Total students in F = 1584 + 1936 = 3520 Total number of students in all six schools = $360 \over 115.2$ x 3520 = 11000 Reqd % = $1584 \over 11000$ x 100 = 14.4 %