Tuesday, 25 January 2022

SBI Clerk Day 2 Numerical Ability Online Test 2

SBI Clerk Day 2 Numerical Ability Online Test 2


1.  Directions(Q.1 to Q.10 ):

What should come in place of the question mark (?) in the following questions ?


28677 ÷ ? = 79 × 11

a
  35
b
  33
c
  1089
d
  1225
e
  None of these
Answer & Explanation
Answer : Option C
Explanation :

28677?=79×11\frac{28677}{\sqrt{?}}=79 \times 11

?=2867779×11=33\Rightarrow \sqrt{?}=\frac{28677}{79 \times 11}=33

?=33×33=1089\therefore ?=33 \times 33=1089

2. 

16×12+3812×825=?\frac{16 \times 12+38}{12 \times 8-25}=?

a
  2122 \frac{1}{2}
b
  37713 \frac{7}{71}
c
  211702 \frac{11}{70}
d
  4351424 \frac{35}{142}
e
  None of these
Answer & Explanation
Answer : Option E
Explanation :

?=192+389625?=\frac{192+38}{96-25}

=23071=31771=\frac{230}{71}=3 \frac{17}{71}

3. 

2376 ÷ 32= ?

a
  67
b
  64.5
c
  74.25
d
  0.69
e
  None of these
Answer & Explanation
Answer : Option C
Explanation :

?=237632=74.25?=\frac{2376}{32}=74.25

4. 

7167 \frac{1}{6} of 186+565=2100?186+565=2100-?

a
  172
b
  202
c
  222
d
  182
e
  None of these
Answer & Explanation
Answer : Option B
Explanation :

186×436+565=2100?186 \times \frac{43}{6}+565=2100-?

Ÿ 1333 + 565 = 2100 – ?

Ÿ 1898 = 2100 – ?

Ÿ ? = 2100 – 1898 = 202

5. 

12321 = ?

a
  91
b
  81
c
  111
d
  121
e
  None of these
Answer & Explanation
Answer : Option C
Explanation :

?=12321=111×111?=\sqrt{12321}=\sqrt{111 \times 111}

=111=111

6. 

67539 + 43908 = ? + 78902

a
  33555
b
  32455
c
  30125
d
  31265
e
  None of these
Answer & Explanation
Answer : Option E
Explanation :

? = (67539 + 43908) – 78902

= 111447 – 78902 = 32545

7. 

12.6 × 10.2 × 6.5 = ?

a
  675.58
b
  555.68
c
  755.48
d
  835.38
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

? = 12.6 × 10.2 × 6.5

= 835.38

8. 

12540 ÷ 55 ÷ 6 = ?

a
  32
b
  44
c
  46
d
  38
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

?=1254055×6=38?=\frac{12540}{55 \times 6}=38

9. 

48% of 840 = 36% of ?

a
  1320
b
  1240
c
  1080
d
  720
e
  None of these
Answer & Explanation
Answer : Option E
Explanation :

?×36100=840×4836? \times \frac{36}{100}=\frac{840 \times 48}{36}

?=840×4836=1120\Rightarrow ?=\frac{840 \times 48}{36}=1120

10. 

45% of 300 + ? = 56% of 750 – 10% of 250

a
  60
b
  67600
c
  130
d
  260
e
  None of these
Answer & Explanation
Answer : Option B
Explanation :

300×45100+?\frac{300 \times 45}{100}+\sqrt{?}

=750×56100250×10100=\frac{750 \times 56}{100}-\frac{250 \times 10}{100}

135+?=42025=395\Rightarrow 135+\sqrt{?}=420-25=395

?=395135=260\Rightarrow \sqrt{?}=395-135=260

?=260×260=67600\Rightarrow ?=260 \times 260=67600

11.  Directions(Q.11 to Q.15 ):

What will come in the place of the question mark (?) in the following number series?


9 11 16 26 ? 69

a
  40
b
  43
c
  41
d
  42
e
  None of these.
Answer & Explanation
Answer : Option B
Explanation :
The pattern is : 9 + 2 (= 12 + 1) = 11 11 + 5 (= 22 + 1) = 16 16 + 10 (= 32 + 1) = 26

43 + 26 (= 52 + 1) = 69

12. 

6 3 3 6 24 ?

a
  192
b
  191
c
  190
d
  189
e
  None of these.
Answer & Explanation
Answer : Option A
Explanation :
The pattern is : 6×12=36 \times \frac{1}{2}=3 3 × 1 = 3 3 × 2 = 6 6 × 4 = 24
13. 

21 24 32 45 63 ?

a
  86
b
  84
c
  85
d
  82
e
  None of these.
Answer & Explanation
Answer : Option A
Explanation :
The pattern is : 21 + 3 = 24 24 + 8 (= 3 + 5) = 32 32 + 13 (= 8 + 5) = 45 45 + 18 (= 13 + 5) = 63
14. 

3 4 10 33 136 ? 4116

a
  700
b
  695
c
  685
d
  590
e
  None of these.
Answer & Explanation
Answer : Option C
Explanation :
The pattern is : 3 × 1 + 1 = 3 + 1 = 4 4 × 2 + 2 = 8 + 2 = 10 10 × 3 + 3 = 30 + 3 = 33 33 × 4 + 4 = 132 + 4 = 136

685 × 6 + 6 = 4110 + 6 = 4116

15. 

7 10 16 28 ? 100

a
  50
b
  53
c
  49
d
  51
e
  52
Answer & Explanation
Answer : Option E
Explanation :
The pattern is : 7 + 3 = 10 10 + 6 (= 2 × 3) = 16 16 + 12 (= 2 × 6) = 28

52 + 48 (= 2 × 24) = 100

16.  Directions(Q.16 to Q.35 ):

Study the table and answer the given questions.

Marks (out of 100) of 5 students A, B, C, D and E in class tests on different days of a week.


The difference between 67% of a number and 43% of the same number is 912. What is 19% of that number ?

a
  722
b
  608
c
  684
d
  798
e
  None of these
Answer & Explanation
Answer : Option A
Explanation :

Let the number be x .

According to the question,

(67 – 43)% of x = 912

x×24100=912\Rightarrow x \times \frac{24}{100}=912

x=912×10024=3800\Rightarrow x=\frac{912 \times 100}{24}=3800

19%\therefore 19 \% of 3800=3800×191003800=\frac{3800 \times 19}{100}

=722=722

17. 

The owner of a computer shop charges his customer 13% more than the cost price. If a customer paid Rs. 15, 933 for a computer, then what was the cost price of the computer ?

a
  Rs. 18,200
b
  Rs. 12,700
c
  Rs. 16,500
d
  Rs. 14,100
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

Cost price of computer

== Rs. (100113×15933)=\left(\frac{100}{113} \times 15933\right)= Rs. 14100

18. 

The cost of 12 note-books and 16 pens is Rs. 852. What is the cost of 9 note-books and 12 pens?

a
  Rs. 639
b
  Cannot be determined
c
  Rs. 567
d
  Rs. 743
e
  None of these
Answer & Explanation
Answer : Option A
Explanation :

Let the CP of 1 note book

= Rs. x and CP of 1 pen = Rs. y.

According to the question,

12x + 16y = 852

Dividing both sides by 4,

3x + 4y = 213

Ÿ 3(3x + 4y) = 3 × 213

Ÿ 9x + 12y = 639

19. 

If an amount of Rs. 85,470 is distributed equally amongst 35 children, how much amount would each child get ?

a
  Rs. 2,552
b
  Rs. 2,542
c
  Rs. 2,452
d
  Rs. 2,442
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

Amount received by each child

== Rs. (8547035)=\left(\frac{85470}{35}\right)= Rs. 2442

20. 

A sum of money is divided among A, B, C and D in the ratio of 3 : 7 : 9 : 13 respectively. If the share of B is Rs. 4,872, then what is the total amount of money of A and C together ?

a
  Rs. 7,456
b
  Rs. 9,784
c
  Rs. 6,998
d
  Rs. 8,352
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

Let the total amount = Rs. x.

Sum of the ratios

= 3 + 7 + 9 + 13 = 32

B’s share = Rs. 4872

x×732=4872\Rightarrow x \times \frac{7}{32}=4872

x=4872×327\Rightarrow x=\frac{4872 \times 32}{7}

= Rs. 22272

? Amount received by A and C

== Rs. (1232×22272)\left(\frac{12}{32} \times 22272\right)

= Rs. 8352.

21. 

The average age of a man and his son is 18 years. The ratio of their ages is 5 : 1 respectively. What will be the ratio of their ages after 6 years ?

a
  10 : 3
b
  5 : 2
c
  3 : 1
d
  4 : 3
e
  None of these.
Answer & Explanation
Answer : Option C
Explanation :

Let the present age of the man = 5x years and that of son

= x years.

According to the question,

5x + x = 18 × 2

6x=36x=366=6\Rightarrow 6 x=36 \Rightarrow x=\frac{36}{6}=6

:Man’s present age = 5 × 6

= 30 years

Son’s present age = 6 years

:Required ratio after 6 years

= 36 : 12 = 3 : 1

22. 

In a class of 40 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 20% of the total number of students. How many sweets were there ?

a
  260
b
  240
c
  360
d
  320
e
  None of these.
Answer & Explanation
Answer : Option E
Explanation :

Number of sweets given to

all students

=40×40×15100=240=40 \times 40 \times \frac{15}{100}=240

Number of sweets given to all

teachers =5×40×20100=5 \times 40 \times \frac{20}{100}

=40=40

Number of all sweets

= 240 + 40 = 280

23. 

A single person takes 6 minutes to fill a bottle. If from 11 a.m. to 12.30 p.m. 1845 bottles are to be filled, how many persons should be employed on this job ?

a
  121
b
  135
c
  139
d
  127
e
  None of these.
Answer & Explanation
Answer : Option E
Explanation :
where x = number of men

Ÿ 90 × x = 6 × 1845

x=6×184590=123\Rightarrow x=\frac{6 \times 1845}{90}=123

24. 

In an examination it is required to get 310 of the aggregate marks to pass. A student gets 28% marks and is declared failed by 93 marks. What are the maximum aggregate marks a student can get ?

a
  765
b
  Cannot be determined
c
  775
d
  685
e
  None of these
Answer & Explanation
Answer : Option C
Explanation :

28% of maximum marks

= 310 – 93 = 217

Ÿ Maximum aggregate marks

=217×10028=775=\frac{217 \times 100}{28}=775

25. 

What is the difference between total score of B on Monday, Wednesday and Thursday together and the total score of E on Tuesday, Wednesday and Friday together?

a
  20
b
  14
c
  12
d
  10
e
  None of these
Answer & Explanation
Answer : Option B
Explanation :

Total marks obtained by B on Monday, Wednesday and Thursday = 65 + 82 + 72 = 219 Total marks obtained by E on Tuesday, Wednesday and Friday = 72 + 59 + 74 = 205

Required difference = 219 – 205 = 14

26. 

If (96)2 is added to the square of a number, the answer so obtained is 16441. What is the number ?

a
  91
b
  89
c
  73
d
  67
e
  None of these.
Answer & Explanation
Answer : Option E
Explanation :

Let the number be x.

According to the question,

x2 + (96)2 = 16441

Ÿ x2 + 9216 = 16441

Ÿ x2 = 16441 – 9216 = 7225

x=7225=85\Rightarrow x=\sqrt{7225}=85

27. 

What is the respective ratio of total marks scored by C on Tuesday and Wednesday together to the total marks scored by D on the same days together?

a
  28 : 23
b
  23 : 28
c
  29 : 23
d
  23 : 29
e
  None of these
Answer & Explanation
Answer : Option C
Explanation :

Required ratio

= (70 + 75) : (51 + 64)

= 145 : 115

= 29 : 23

28. 

Marks of E on Monday are what per cent more than marks of B on Thursday?

a
  15%
b
  20%
c
  25%
d
  1623%16 \frac{2}{3} \%
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

Required percentage

=(847272)×100=\left(\frac{84-72}{72}\right) \times 100

=120072=503=1623%=\frac{1200}{72}=\frac{50}{3}=16 \frac{2}{3} \%

29. 

What is the compound interest accrued on an amount of Rs. 15,000, at the rate of 11.p.c.p.a. at the end of 3 years ?

a
  Rs. 3,575.565
b
  Rs. 4,935.895
c
  Rs. 5,825.345
d
  Rs. 5,514.465
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

C.I. =P[(1+R100)T1]=\mathrm{P}\left[\left(1+\frac{\mathrm{R}}{100}\right)^{\mathrm{T}}-1\right]

=15000[(1+11100)31]=15000\left[\left(1+\frac{11}{100}\right)^{3}-1\right]

=15000[(1.11)31]=15000\left[(1.11)^{3}-1\right]

= 15000 (1.367631 –1)

= 15000 × 0.367631

= Rs. 5514.465

30. 

What is the average marks scored by C on the given days?

a
  60
b
  62
c
  64
d
  52
e
  None of these.
Answer & Explanation
Answer : Option C
Explanation :

Average marks of C

=36+70+75+62+775=\frac{36+70+75+62+77}{5}

=3205=64=\frac{320}{5}=64

31. 

Which number should replace both question marks (?) in the following equation ? ?176=44?\frac{?}{176}=\frac{44}{?}

a
  92
b
  76
c
  132
d
  88
e
  None of these.
Answer & Explanation
Answer : Option D
Explanation :

(?)2 = 176 × 44 = 44 × 4 × 44

? = 44 × 2 = 88

32. 

One-fifth of a number is 48. What will be 62% of that number ?

a
  164.66
b
  178.22
c
  148.8
d
  182.44
e
  None of these
Answer & Explanation
Answer : Option C
Explanation :

Let the number be x.

According to the question,

x5=48x=5×48=240\frac{x}{5}=48 \Rightarrow x=5 \times 48=240

=62% of 240100=148.8=\frac{62 \% \text { of } 240}{100}=148.8

33. 

42 per cent of first number is 56 per cent of the second number. What is the respective ratio of the first number to the second number ?

a
  Cannot be determined
b
  4 : 3
c
  31 : 42
d
  4 : 5
e
  None of these
Answer & Explanation
Answer : Option B
Explanation :

Let the first number be x and the second number be y.

According to the question,

x×42100=y×56100xy=5642=43\begin{aligned} & x \times \frac{42}{100}=y \times \frac{56}{100} \\ \Rightarrow & \frac{x}{y}=\frac{56}{42}=\frac{4}{3} \end{aligned}

34. 

Mr. Vijay deposits an amount of Rs. 45,500 to obtain a simple interest at the rate of 11 p.c.p.a for 3 years. What total amount will Mr. Vijay get at the end of 3 years?

a
  Rs. 62,015
b
  Rs. 65,515
c
  Rs. 60,015
d
  Rs. 60,515
e
  None of these
Answer & Explanation
Answer : Option D
Explanation :

S.I. = Principal × Time × Rate 100=\frac{\text { Principal } \times \text { Time } \times \text { Rate }}{100}

=45500×3×111100==\frac{45500 \times 3 \times 111}{100}= Rs. 15015

Required amount

= Rs. (45500 + 15015) = Rs. 60515

35. 

Total marks scored by E on all days together are how much more than total marks scored by A on all days together?

a
  55
b
  45
c
  43
d
  65
e
  None of these.
Answer & Explanation
Answer : Option E
Explanation :

Total marks of A = 74 + 69

+ 49 + 55 + 67 = 314

Total marks of E = 84 + 72 +

59 + 68 + 74 = 357

Required per cent

=(357314314)×100=\left(\frac{357-314}{314}\right) \times 100

=430031414%=\frac{4300}{314} \approx 14 \%

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