| Answers & Solutions | | 1 . | Answer : Option C | Explanation : | Let Amit's spped be x key depressions per day. Sujit's speed 4x54x554x key depressions per day 5××× + 5 ××× 4x54x554x = 576000 ⇒⇒⇒ 9 xxx = 576000 ⇒⇒⇒ xxx = 576000957600099576000 = 64000 Amit's speed per hour = 640008640008864000= 8000 | | | 2 . | Answer : Option A | Explanation : | 4 × 2 men ≅≅≅4 × 4 women = 20 children 2 men ≅≅≅ 4 women ≅≅≅ 5 children 2 men + 4 women + 10 children = 20 children M1D1=M2D2M1D1=M2D2M1D1=M2D2 5 x 4 = 20 x D222 ⇒⇒⇒ D222 = 1 day | | | 3 . | Answer : Option D | Explanation : | Days Men 10$\uparrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,121212\downarrow$ 8$\uparrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\downarrow$ Where xxx= No. of Men 8 : 10 :: 12 : xxx ⇒⇒⇒ 8×x=10×128×x=10×128×x=10×12 ⇒⇒⇒ x = 10+12810+128810+12 = 15 | | | 4 . | Answer : Option C | Explanation : | A’s 1 day’s work = 112112121 (A + B)’s 1 day’s work = 181881 B’s 1 day’s work = 181881 - 112112121 = 3−2243−224243−2 = 124241 B alone can do the work in 24 days. | | | 5 . | Answer : Option B | Explanation : | In 36 days 12 men can do 1 complete work. In 36 days 12 women can do 3443 th of the work Since time and the no, of persons in the same is both casses, 1 woman’s daily work 3443 th of 1 man’s daily work 8 woman’s daily work = 3443 × 8 = 6 meri’s daily work (10 men + 8 womens daily work) = (10 men + 6 men) = 16 men’s daily work. 12 men can do the work is 36 days 16 men can do the work is 36 × 12161612 = 27 days. | | | 6 . | Answer : Option B | Explanation : | 2 men = 1 woman 1 man = 1221 women 3 men = 3223 women Again, 2 children = 1 man = 1221 women 1 child = 1441 women 6 children = 6446 = 3223 women Now, three men, four women and six children = 3223 + 4 + 3223 = 7 women Hence, 7 women complete the work in 7 days
| | | 7 . | Answer : Option B | Explanation : | Work done in 1st two days = 110101 + 115151 = 3+230303+2 = 1661 Number of days = 12 | | | 8 . | Answer : Option D | Explanation : | M1D1W1W1M1D1 = M2D2W2W2M2D2 ⇒⇒ 6×6W1W16×6 = 9×10119×10 ⇒⇒ W1W1 = 6×69×109×106×6 = 2552 Part of work done by 6 women in 6 days = 2552 Part of work done by 6 men in 6 days = 1 – 2552 = 3553 M1D1W1W1M1D1 = M2D2W2W2M2D2 ⇒⇒ 6×6W1W16×6 ⇒⇒ 6×635536×6 = 15×D21115×D2 ⇒⇒ 15×D215×D2 = 6×6×5336×6×5 = 60 ⇒⇒ D2D2 = 60151560 = 4 day
| | | 9 . | Answer : Option C | Explanation : | Examiners Work Days Hours / day 4$\uparrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,11\downarrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1010\uparrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,55\downarrow$ 2$\uparrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,22\downarrow\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2020\uparrowx\downarrow$ (2 : 4), (1 : 2) & (20 : 10) :: (5 : xx) $\Rightarrow2 \times 20 \times x= 4 × 10 × 5 × 2$ ⇒⇒ xx = 4×10×5×22×202×204×10×5×2 = 10 hours | | | | |
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