SBI PO Quantitative Aptitude Quiz 1

1 . Directions (1–8): What approximate value should come in place of the question mark (?) in the following? (You are not expected to calculate the exact value). 8787 ÷ 343 × $\sqrt 50$ = ? A.   100 B.   250 C.   180 D.   100 2 . $\sqrt [3]{54821}$ × (303 ÷ 8) = $(?)^2$ A.   48 B.   38 C.   28 D.   18 3 . $5\over8 $ of 4011.33 +$7\over10 $ of 3411.22 = ? A.   4810 B.   4820 C.   4890 D.   4860 4 . 23% of 6783 + 57% of 8431 = ? A.   6460 B.   6420 C.   6480 D.   6360 5 . Ratio of cost price and marked price of an article is 3:5. Ratio of profit percentage and discount percentage is 5:3. Find discount percentage? A.   10% B.   10÷3 C.   20% D.   5% 6 . A can do a piece of work in the days taken by B and C together A and B can do piece of work in 10 days and C can do in 50 days. Find in how many days B alone can complete the work? A.   25 B.   35 C.   45 D.   7 . 10 year ago A was 3 times of the age of B and hence, after 10 years, he will be twice the age of B. Find the respective ratio of their present age. A.   7:3 B.   3:7 C.   1:2 D.   2:1 8 . A boat goes in a running water flowing at the rate of 1.5 kmph. In a given time, boat goes twice the distance in downstream than upstream. Find speed of the boat in still water. A.   4.5 B.   3 C.   5 D.   None of the Above 9 . If a train is going at the rate of 40 kmph, it is late by 11 min. If it is going at the rate of 50 kmph, it is late by 5 mins to reach at a destination. Find actual time to complete the journey. A.   30min. B.   35min C.   19min D.   None of the above

Answers & Solutions   1 .   Answer & Explanation Answer : Option C   Explanation :   ═ ? =$8787\over 343$ × $\sqrt 50$ = 25.62 × 7 = 26 × 7 = 182 180 Answer : Option C   Explanation :   ═ ? =$8787\over 343$ × $\sqrt 50$ = 25.62 × 7 = 26 × 7 = 182 180 2 .   Answer & Explanation Answer : Option B   Explanation :   $\sqrt [3]{54821}$× (303 ÷ 8) = $(?)^2$ $\sqrt [3]{54821}$ X [$303\over8$] $(?)^2$ = 38 × 38 ? = 38 Answer : Option B   Explanation :   $\sqrt [3]{54821}$× (303 ÷ 8) = $(?)^2$ $\sqrt [3]{54821}$ X [$303\over8$] $(?)^2$ = 38 × 38 ? = 38 3 .   Answer & Explanation Answer : Option C   Explanation :   (3) ? = 4011.33 × $5\over8 $+3411.22 × $7\over10 $ = 501.41× 5 + 341.12 × 7= 2507 + 2387 = 4894 = 4890 Answer : Option C   Explanation :   (3) ? = 4011.33 × $5\over8 $+3411.22 × $7\over10 $ = 501.41× 5 + 341.12 × 7= 2507 + 2387 = 4894 = 4890 4 .   Answer & Explanation Answer : Option D   Explanation :   (5) ? = 6783 × $23\over100 $+ 8431 × $57\over100 $ = ? $156009\over100 $ + $4805670\over100 $ = $636576\over100 $ =6365.76 = 6360 Answer : Option D   Explanation :   (5) ? = 6783 × $23\over100 $+ 8431 × $57\over100 $ = ? $156009\over100 $ + $4805670\over100 $ = $636576\over100 $ =6365.76 = 6360 5 .   Answer & Explanation Answer : Option C   Explanation :   C.P. : M.R.P 3x : 5x P% : D% 5y : 3y S.P. = S.P. 3x + $3x+5y\over100 $ = 5x + $5x+3y\over100 $ Y= $20\over3$ D% = 3y = 20% Answer : Option C   Explanation :   C.P. : M.R.P 3x : 5x P% : D% 5y : 3y S.P. = S.P. 3x + $3x+5y\over100 $ = 5x + $5x+3y\over100 $ Y= $20\over3$ D% = 3y = 20% 6 .   Answer & Explanation Answer : Option A   Explanation :   Answer : Option A   Explanation :   7 .   Answer & Explanation Answer : Option A   Explanation :   A : B 3 : 1 – 10 years before 2 : 1 – After 10 years equating difference we get So, 3 unit = 60 years Thus, in present A and B's age is 70 years and 30 years respectively. ratio = 7 : 3. Answer : Option A   Explanation :   A : B 3 : 1 – 10 years before 2 : 1 – After 10 years equating difference we get So, 3 unit = 60 years Thus, in present A and B's age is 70 years and 30 years respectively. ratio = 7 : 3. 8 .   Answer & Explanation Answer : Option A   Explanation :   (1) As, the time is equal for downstream and upsteam distance. Now,, $Distance\over speed$ = $29(Distance)\over speed$ $X\over M-1.5$ = $ 2X\over M+1.5$ M = 4.5 Answer : Option A   Explanation :   (1) As, the time is equal for downstream and upstream distance. Now,, $Distance\over speed$ = $29(Distance)\over speed$ $X\over M-1.5$ = $ 2X\over M+1.5$ M = 4.5 9 .   Answer & Explanation Answer : Option A   Explanation :   x = Actual time in minutes. S × T = S × T 40 × $X+11\over60$ = 50 × $X+5\over60$ x = 19 minutes. Answer : Option A   Explanation :   x = Actual time in minutes. S × T = S × T 40 × $X+11\over60$ = 50 × $X+5\over60$ x = 19 minutes.